Integrand size = 22, antiderivative size = 22 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=-\frac {b \cos \left (2 a-\frac {2 b c}{d}\right ) \operatorname {CosIntegral}\left (\frac {2 b c}{d}+2 b x\right )}{d^2}+\frac {\sin (2 a+2 b x)}{2 d (c+d x)}+\frac {b \sin \left (2 a-\frac {2 b c}{d}\right ) \text {Si}\left (\frac {2 b c}{d}+2 b x\right )}{d^2}+\text {Int}\left (\frac {\cot (a+b x)}{(c+d x)^2},x\right ) \]
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Not integrable
Time = 0.19 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\cot (a+b x)}{(c+d x)^2} \, dx-\int \frac {\cos (a+b x) \sin (a+b x)}{(c+d x)^2} \, dx \\ & = \int \frac {\cot (a+b x)}{(c+d x)^2} \, dx-\int \frac {\sin (2 a+2 b x)}{2 (c+d x)^2} \, dx \\ & = -\left (\frac {1}{2} \int \frac {\sin (2 a+2 b x)}{(c+d x)^2} \, dx\right )+\int \frac {\cot (a+b x)}{(c+d x)^2} \, dx \\ & = \frac {\sin (2 a+2 b x)}{2 d (c+d x)}-\frac {b \int \frac {\cos (2 a+2 b x)}{c+d x} \, dx}{d}+\int \frac {\cot (a+b x)}{(c+d x)^2} \, dx \\ & = \frac {\sin (2 a+2 b x)}{2 d (c+d x)}-\frac {\left (b \cos \left (2 a-\frac {2 b c}{d}\right )\right ) \int \frac {\cos \left (\frac {2 b c}{d}+2 b x\right )}{c+d x} \, dx}{d}+\frac {\left (b \sin \left (2 a-\frac {2 b c}{d}\right )\right ) \int \frac {\sin \left (\frac {2 b c}{d}+2 b x\right )}{c+d x} \, dx}{d}+\int \frac {\cot (a+b x)}{(c+d x)^2} \, dx \\ & = -\frac {b \cos \left (2 a-\frac {2 b c}{d}\right ) \operatorname {CosIntegral}\left (\frac {2 b c}{d}+2 b x\right )}{d^2}+\frac {\sin (2 a+2 b x)}{2 d (c+d x)}+\frac {b \sin \left (2 a-\frac {2 b c}{d}\right ) \text {Si}\left (\frac {2 b c}{d}+2 b x\right )}{d^2}+\int \frac {\cot (a+b x)}{(c+d x)^2} \, dx \\ \end{align*}
Not integrable
Time = 2.88 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx \]
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Not integrable
Time = 1.00 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00
\[\int \frac {\cos \left (x b +a \right )^{2} \cot \left (x b +a \right )}{\left (d x +c \right )^{2}}d x\]
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Not integrable
Time = 0.25 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.59 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int { \frac {\cos \left (b x + a\right )^{2} \cot \left (b x + a\right )}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 1.26 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int \frac {\cos ^{2}{\left (a + b x \right )} \cot {\left (a + b x \right )}}{\left (c + d x\right )^{2}}\, dx \]
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Not integrable
Time = 0.88 (sec) , antiderivative size = 343, normalized size of antiderivative = 15.59 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int { \frac {\cos \left (b x + a\right )^{2} \cot \left (b x + a\right )}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 2.36 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int { \frac {\cos \left (b x + a\right )^{2} \cot \left (b x + a\right )}{{\left (d x + c\right )}^{2}} \,d x } \]
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Not integrable
Time = 26.52 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {\cos ^2(a+b x) \cot (a+b x)}{(c+d x)^2} \, dx=\int \frac {{\cos \left (a+b\,x\right )}^2\,\mathrm {cot}\left (a+b\,x\right )}{{\left (c+d\,x\right )}^2} \,d x \]
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